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Download Databricks Certified Associate Developer for Apache Spark 3.0 Exam Exam Dumps

NEW QUESTION 48
Which of the following describes Spark's way of managing memory?

  • A. Storage memory is used for caching partitions derived from DataFrames.
  • B. Spark uses a subset of the reserved system memory.
  • C. Disabling serialization potentially greatly reduces the memory footprint of a Spark application.
  • D. Spark's memory usage can be divided into three categories: Execution, transaction, and storage.
  • E. As a general rule for garbage collection, Spark performs better on many small objects than few big objects.

Answer: A

Explanation:
Explanation
Spark's memory usage can be divided into three categories: Execution, transaction, and storage.
No, it is either execution or storage.
As a general rule for garbage collection, Spark performs better on many small objects than few big objects.
No, Spark's garbage collection runs faster on fewer big objects than many small objects.
Disabling serialization potentially greatly reduces the memory footprint of a Spark application.
The opposite is true - serialization reduces the memory footprint, but may impact performance in a negative way.
Spark uses a subset of the reserved system memory.
No, the reserved system memory is separate from Spark memory. Reserved memory stores Spark's internal objects.
More info: Tuning - Spark 3.1.2 Documentation, Spark Memory Management | Distributed Systems Architecture, Learning Spark, 2nd Edition, Chapter 7

 

NEW QUESTION 49
Which of the following code blocks returns a single-column DataFrame of all entries in Python list throughputRates which contains only float-type values ?

  • A. spark.createDataFrame(throughputRates, FloatType())
  • B. spark.createDataFrame(throughputRates, FloatType)
  • C. spark.DataFrame(throughputRates, FloatType)
  • D. spark.createDataFrame(throughputRates)
  • E. spark.createDataFrame((throughputRates), FloatType)

Answer: A

Explanation:
Explanation
spark.createDataFrame(throughputRates, FloatType())
Correct! spark.createDataFrame is the correct operator to use here and the type FloatType() which is passed in for the command's schema argument is correctly instantiated using the parentheses.
Remember that it is essential in PySpark to instantiate types when passing them to SparkSession.createDataFrame. And, in Databricks, spark returns a SparkSession object.
spark.createDataFrame((throughputRates), FloatType)
No. While packing throughputRates in parentheses does not do anything to the execution of this command, not instantiating the FloatType with parentheses as in the previous answer will make this command fail.
spark.createDataFrame(throughputRates, FloatType)
Incorrect. Given that it does not matter whether you pass throughputRates in parentheses or not, see the explanation of the previous answer for further insights.
spark.DataFrame(throughputRates, FloatType)
Wrong. There is no SparkSession.DataFrame() method in Spark.
spark.createDataFrame(throughputRates)
False. Avoiding the schema argument will have PySpark try to infer the schema. However, as you can see in the documentation (linked below), the inference will only work if you pass in an "RDD of either Row, namedtuple, or dict" for data (the first argument to createDataFrame). But since you are passing a Python list, Spark's schema inference will fail.
More info: pyspark.sql.SparkSession.createDataFrame - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 50
Which of the following code blocks shuffles DataFrame transactionsDf, which has 8 partitions, so that it has
10 partitions?

  • A. transactionsDf.repartition(transactionsDf.getNumPartitions()+2)
  • B. transactionsDf.repartition(transactionsDf.rdd.getNumPartitions()+2)
  • C. transactionsDf.repartition(transactionsDf._partitions+2)
  • D. transactionsDf.coalesce(10)
  • E. transactionsDf.coalesce(transactionsDf.getNumPartitions()+2)

Answer: B

Explanation:
Explanation
transactionsDf.repartition(transactionsDf.rdd.getNumPartitions()+2)
Correct. The repartition operator is the correct one for increasing the number of partitions. calling getNumPartitions() on DataFrame.rdd returns the current number of partitions.
transactionsDf.coalesce(10)
No, after this command transactionsDf will continue to only have 8 partitions. This is because coalesce() can only decreast the amount of partitions, but not increase it.
transactionsDf.repartition(transactionsDf.getNumPartitions()+2)
Incorrect, there is no getNumPartitions() method for the DataFrame class.
transactionsDf.coalesce(transactionsDf.getNumPartitions()+2)
Wrong, coalesce() can only be used for reducing the number of partitions and there is no getNumPartitions() method for the DataFrame class.
transactionsDf.repartition(transactionsDf._partitions+2)
No, DataFrame has no _partitions attribute. You can find out the current number of partitions of a DataFrame with the DataFrame.rdd.getNumPartitions() method.
More info: pyspark.sql.DataFrame.repartition - PySpark 3.1.2 documentation, pyspark.RDD.getNumPartitions - PySpark 3.1.2 documentation Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 51
Which of the following code blocks creates a new 6-column DataFrame by appending the rows of the
6-column DataFrame yesterdayTransactionsDf to the rows of the 6-column DataFrame todayTransactionsDf, ignoring that both DataFrames have different column names?

  • A. todayTransactionsDf.concat(yesterdayTransactionsDf)
  • B. todayTransactionsDf.unionByName(yesterdayTransactionsDf)
  • C. union(todayTransactionsDf, yesterdayTransactionsDf)
  • D. todayTransactionsDf.unionByName(yesterdayTransactionsDf, allowMissingColumns=True)
  • E. todayTransactionsDf.union(yesterdayTransactionsDf)

Answer: E

Explanation:
Explanation
todayTransactionsDf.union(yesterdayTransactionsDf)
Correct. The union command appends rows of yesterdayTransactionsDf to the rows of todayTransactionsDf, ignoring that both DataFrames have different column names. The resulting DataFrame will have the column names of DataFrame todayTransactionsDf.
todayTransactionsDf.unionByName(yesterdayTransactionsDf)
No. unionByName specifically tries to match columns in the two DataFrames by name and only appends values in columns with identical names across the two DataFrames. In the form presented above, the command is a great fit for joining DataFrames that have exactly the same columns, but in a different order. In this case though, the command will fail because the two DataFrames have different columns.
todayTransactionsDf.unionByName(yesterdayTransactionsDf, allowMissingColumns=True) No. The unionByName command is described in the previous explanation. However, with the allowMissingColumns argument set to True, it is no longer an issue that the two DataFrames have different column names. Any columns that do not have a match in the other DataFrame will be filled with null where there is no value. In the case at hand, the resulting DataFrame will have 7 or more columns though, so it this command is not the right answer.
union(todayTransactionsDf, yesterdayTransactionsDf)
No, there is no union method in pyspark.sql.functions.
todayTransactionsDf.concat(yesterdayTransactionsDf)
Wrong, the DataFrame class does not have a concat method.
More info: pyspark.sql.DataFrame.union - PySpark 3.1.2 documentation,
pyspark.sql.DataFrame.unionByName - PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 52
Which of the following code blocks creates a new DataFrame with 3 columns, productId, highest, and lowest, that shows the biggest and smallest values of column value per value in column productId from DataFrame transactionsDf?
Sample of DataFrame transactionsDf:
1.+-------------+---------+-----+-------+---------+----+
2.|transactionId|predError|value|storeId|productId| f|
3.+-------------+---------+-----+-------+---------+----+
4.| 1| 3| 4| 25| 1|null|
5.| 2| 6| 7| 2| 2|null|
6.| 3| 3| null| 25| 3|null|
7.| 4| null| null| 3| 2|null|
8.| 5| null| null| null| 2|null|
9.| 6| 3| 2| 25| 2|null|
10.+-------------+---------+-----+-------+---------+----+

  • A. transactionsDf.groupby('productId').agg(max('value').alias('highest'), min('value').alias('lowest'))
  • B. transactionsDf.groupby("productId").agg({"highest": max("value"), "lowest": min("value")})
  • C. transactionsDf.max('value').min('value')
  • D. transactionsDf.groupby(col(productId)).agg(max(col(value)).alias("highest"), min(col(value)).alias("lowest"))
  • E. transactionsDf.agg(max('value').alias('highest'), min('value').alias('lowest'))

Answer: A

Explanation:
Explanation
transactionsDf.groupby('productId').agg(max('value').alias('highest'), min('value').alias('lowest')) Correct. groupby and aggregate is a common pattern to investigate aggregated values of groups.
transactionsDf.groupby("productId").agg({"highest": max("value"), "lowest": min("value")}) Wrong. While DataFrame.agg() accepts dictionaries, the syntax of the dictionary in this code block is wrong.
If you use a dictionary, the syntax should be like {"value": "max"}, so using the column name as the key and the aggregating function as value.
transactionsDf.agg(max('value').alias('highest'), min('value').alias('lowest')) Incorrect. While this is valid Spark syntax, it does not achieve what the question asks for. The question specifically asks for values to be aggregated per value in column productId - this column is not considered here. Instead, the max() and min() values are calculated as if the entire DataFrame was a group.
transactionsDf.max('value').min('value')
Wrong. There is no DataFrame.max() method in Spark, so this command will fail.
transactionsDf.groupby(col(productId)).agg(max(col(value)).alias("highest"), min(col(value)).alias("lowest")) No. While this may work if the column names are expressed as strings, this will not work as is. Python will interpret the column names as variables and, as a result, pySpark will not understand which columns you want to aggregate.
More info: pyspark.sql.DataFrame.agg - PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 3

 

NEW QUESTION 53
......

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